return to home page Computational Chemistry Comparison and Benchmark DataBase Release 22 (May 2022) Standard Reference Database 101 National Institute of Standards and Technology
You are here: Calculated > Energy > Optimized > Energy

All results from a given calculation for C3H4O2 (propenalol)

using model chemistry: LSDA/6-31G(2df,p)

19 10 17 12 22

States and conformations

State Conformation minimum conformation conformer description state description
1 1 yes CS 1A'
Energy calculated at LSDA/6-31G(2df,p)
 hartrees
Energy at 0K-265.784805
Energy at 298.15K-265.789737
Nuclear repulsion energy168.605234
The energy at 298.15K was derived from the energy at 0K and an integrated heat capacity that used the calculated vibrational frequencies.
Vibrational Frequencies calculated at LSDA/6-31G(2df,p)
Mode Number Symmetry Frequency
(cm-1)
Scaled Frequency
(cm-1)
IR Intensities
(km mol-1)
Raman Act
4/u)
Dep P Dep U
1 A' 3188 3137 0.03      
2 A' 3001 2953 17.98      
3 A' 2999 2951 45.64      
4 A' 1825 1796 109.20      
5 A' 1702 1674 606.04      
6 A' 1651 1625 127.87      
7 A' 1486 1462 50.06      
8 A' 1346 1324 60.29      
9 A' 1303 1282 25.12      
10 A' 1070 1053 0.35      
11 A' 1061 1044 0.07      
12 A' 924 910 1.14      
13 A' 609 599 0.22      
14 A' 559 550 11.42      
15 A' 186 183 236.71      
16 A" 1248 1228 67.75      
17 A" 999 983 0.00      
18 A" 943 928 0.86      
19 A" 760 748 23.15      
20 A" 370 364 12.41      
21 A" 364 359 0.02      

Unscaled Zero Point Vibrational Energy (zpe) 13796.0 cm-1
Scaled (by 0.984) Zero Point Vibrational Energy (zpe) 13575.3 cm-1
See section III.C.1 List or set vibrational scaling factors to change the scale factors used here.
See section III.C.2 Calculate a vibrational scaling factor for a given set of molecules to determine the least squares best scaling factor.
Rotational Constants (cm-1) from geometry optimized at LSDA/6-31G(2df,p)
ABC
0.32734 0.19260 0.12125

See section I.F.4 to change rotational constant units
Geometric Data calculated at LSDA/6-31G(2df,p)

Point Group is Cs

Cartesians (Å)
Atom x (Å) y (Å) z (Å)
C1 0.000 1.121 0.000
C2 1.180 0.384 0.000
C3 -1.180 0.385 0.000
O4 1.181 -0.887 0.000
O5 -1.181 -0.887 0.000
H6 -0.002 -1.128 0.000
H7 -0.000 2.210 0.000
H8 2.167 0.885 0.000
H9 -2.167 0.885 0.000

Atom - Atom Distances (Å)
  C1 C2 C3 O4 O5 H6 H7 H8 H9
C11.39151.39122.33032.33032.24941.08882.17972.1798
C21.39152.36031.27162.68211.91932.17421.10653.3844
C31.39122.36032.68221.27201.91762.17383.38421.1064
O42.33031.27162.68222.36251.20713.31522.02803.7883
O52.33032.68211.27202.36251.20403.31523.78842.0279
H62.24941.91931.91761.20711.20403.33832.95892.9565
H71.08882.17422.17383.31523.31523.33832.54002.5401
H82.17971.10653.38422.02803.78842.95892.54004.3338
H92.17983.38441.10643.78832.02792.95652.54014.3338

picture of propenalol state 1 conformation 1
More geometry information
Calculated Bond Angles
atom1 atom2 atom3 angle atom1 atom2 atom3 angle
C1 C2 O4 122.034 C1 C2 H8 121.102
C1 C3 O5 122.029 C1 C3 H9 121.144
C2 C1 C3 116.037 C2 C1 H7 121.987
C3 C1 H7 121.976 C3 O5 H6 101.479
O4 C2 H8 116.863 O5 C3 H9 116.827
Electronic energy levels
Charges, Dipole, Quadrupole and Polarizability
Charges from optimized geometry at LSDA/6-31G(2df,p) Charges (e)
Number Element Mulliken CHELPG AIM ESP
1 C -0.262      
2 C 0.037      
3 C 0.037      
4 O -0.320      
5 O -0.319      
6 H 0.389      
7 H 0.143      
8 H 0.148      
9 H 0.148      


Electric dipole moments
Electric dipole components in Debye
(What's a Debye? See section VII.A.3)
  x y z Total
  -0.004 2.407 0.000 2.407
CHELPG        
AIM        
ESP        


Electric Quadrupole moment
Quadrupole components in D Å
Primitive
 xyz
x -27.516 0.002 0.000
y 0.002 -28.243 0.000
z 0.000 0.000 -29.448
Traceless
 xyz
x 1.330 0.002 0.000
y 0.002 0.239 0.000
z 0.000 0.000 -1.568
Polar
3z2-r2-3.136
x2-y20.727
xy0.002
xz0.000
yz0.000


Polarizabilities
Components of the polarizability tensor.
Units are Å3 (Angstrom cubed)
Change units.
  x y z
x 8.132 0.001 0.000
y 0.001 6.327 0.000
z 0.000 0.000 2.970


<r2> (average value of r2) Å2
<r2> 0.000
(<r2>)1/2 0.000